Hej
Alle indekser i SQL Server-databasen vil blive fragmenteret Efter at relaterede tabeller har fået mange opdateringer, skal du slette transaktioner.
SQL Server Rebuild Index
Hvis indekset i tabellen er fragmenteret, vil alle transaktioner relateret til den tabel være meget langsomme. Så SQL Server DBA bør ofte overvåge indekser, og hvilke af indekser der er fragmenterede, og hvilke der ikke er.
SQL Server Reorganize Index
Du kan bruge fragmenteret indeks med følgende procedure. Denne procedure for genopbygning og omorganisering af indekset afhænger af dets situation
CREATE PROC [INDEX_MAINTENANCE] @DBName VARCHAR(100) AS BEGIN SET NOCOUNT ON; DECLARE @OBJECT_ID INT, @INDEX_NAME sysname, @SCHEMA_NAME sysname, @OBJECT_NAME sysname, @AVG_FRAG float, @command varchar(8000), @RebuildCount int, @ReOrganizeCount int CREATE TABLE #tempIM ( [ID] [INT] IDENTITY(1,1) NOT NULL PRIMARY KEY, [INDEX_NAME] sysname NULL, [OBJECT_ID] INT NULL, [SCHEMA_NAME] sysname NULL, [OBJECT_NAME] sysname NULL, [AVG_FRAG] float ) SELECT @RebuildCount=0,@ReOrganizeCount=0 --Get Fragentation values SELECT @command= 'Use ' + @DBName + '; INSERT INTO #tempIM (OBJECT_ID, INDEX_NAME, SCHEMA_NAME, OBJECT_NAME, AVG_FRAG) SELECT ps.object_id, i.name as IndexName, OBJECT_SCHEMA_NAME(ps.object_id) as ObjectSchemaName, OBJECT_NAME (ps.object_id) as ObjectName, ps.avg_fragmentation_in_percent FROM sys.dm_db_index_physical_stats (NULL, NULL, NULL , NULL, ''LIMITED'') ps INNER JOIN sys.indexes i ON i.object_id=ps.object_id and i.index_id=ps.index_id WHERE avg_fragmentation_in_percent > 5 AND ps.index_id > 0 and ps.database_id=DB_ID('''[email protected]+''') ORDER BY avg_fragmentation_in_percent desc ' exec(@command) DECLARE c CURSOR FAST_FORWARD FOR SELECT OBJECT_ID,INDEX_NAME, SCHEMA_NAME, OBJECT_NAME, AVG_FRAG FROM #tempIM OPEN c FETCH NEXT FROM c INTO @OBJECT_ID, @INDEX_NAME, @SCHEMA_NAME, @OBJECT_NAME, @AVG_FRAG WHILE @@FETCH_STATUS = 0 BEGIN --Reorganize or Rebuild IF @AVG_FRAG>30 BEGIN SELECT @command = 'Use ' + @DBName + '; ALTER INDEX [' + @INDEX_NAME +'] ON [' + @SCHEMA_NAME + '].[' + @OBJECT_NAME + '] REBUILD WITH (ONLINE = ON )'; SET @RebuildCount = @RebuildCount+1 END ELSE BEGIN SELECT @command = 'Use ' + @DBName + '; ALTER INDEX [' + @INDEX_NAME +'] ON [' + @SCHEMA_NAME + '].[' + @OBJECT_NAME + '] REORGANIZE '; SET @ReOrganizeCount = @ReOrganizeCount+1 END BEGIN TRY EXEC (@command); END TRY BEGIN CATCH END CATCH FETCH NEXT FROM c INTO @OBJECT_ID, @INDEX_NAME, @SCHEMA_NAME, @OBJECT_NAME, @AVG_FRAG END CLOSE c DEALLOCATE c DROP TABLE #tempIM SELECT cast(@RebuildCount as varchar(5))+' index Rebuild,'+cast(@ReOrganizeCount as varchar(5))+' index Reorganize is done.' as Result END
Du kan udføre denne procedure med følgende forespørgsel. Indtast databasenavnet i stedet for DEVECI korrekt, og proceduren vil genopbygge og omorganisere relaterede databaseindekser.
exec dbo.INDEX_MAINTENANCE 'DEVECI';