sql >> Database teknologi >  >> RDS >> Mysql

MySql-databasestruktur for:Søg baseret på enkelt kolonne og forskellig værdi

prøv dette:

create table City
    (
     Id int,
     Name varchar(50)
    );

    insert into City (Id, Name) 
    VALUES 
    (1, 'Toronto'), 
    (2, 'Chicago')

    create table Libraries(
    Id int,
    Name varchar(50),
    CityId int
    );

    insert into Libraries (Id, Name, CityId) 
    VALUES 
    (1, 'Toronto Library 1', 1),
    (2, 'Toronto Library 2', 1),
    (3, 'Chicago Library 1', 2),
    (4, 'Chicago Library 2', 2)

    create table Books(
    Id int,
    Isbn varchar(12),
    LibraryId int
    );

    insert into Books (Id, Isbn, LibraryId) 
    Values
    (1, '1234567891', 1),
    (2, '13344555', 1),
    (3, 'x123sada', 1),
    (4, 'xasdsadas', 2),
    (5, 'axxzksda', 2)

    select DISTINCT b.Name 
    from Books a
    inner join Libraries b
    on a.LibraryId = b.Id
    where Isbn in ('1234567891', '13344555')
    and b.CityId = 1

Edit:eller 4NF:

create table City
(
 Id int,
 Name varchar(50)
);

insert into City (Id, Name) 
VALUES 
(1, 'Toronto'), 
(2, 'Chicago')

create table Libraries(
Id int,
Name varchar(50),
CityId int
);

insert into Libraries (Id, Name, CityId) 
VALUES 
(1, 'Toronto Library 1', 1),
(2, 'Toronto Library 2', 1),
(3, 'Chicago Library 1', 2),
(4, 'Chicago Library 2', 2)

create table Books(
Id int,
Isbn varchar(12),
);

insert into Books (Id, Isbn) 
Values
(1, '1234567891'),
(2, '13344555'),
(3, 'x123sada'),
(4, 'xasdsadas'),
(5, 'axxzksda')

create table LibraryBooks
(
LibraryId int,
BookId int
);

insert into LibraryBooks (LibraryId, BookId)
VALUES
(1, 1),
(1, 2),
(3, 1),
(2, 4),
(5, 2)

select DISTINCT c.Name
from Books a
inner join LibraryBooks b
on a.Id = b.BookId
inner join Libraries c on
c.Id = b.LibraryId
where Isbn in ('1234567891', '13344555')
and c.CityId = 1


  1. Rails ActiveRecord - er der en måde at udføre operationer på tabeller uden et id?

  2. SQL Server Linked Server Eksempel forespørgsel

  3. Hvordan kan jeg indstille en dato til NULL i Yii?

  4. Kombiner flere unikke MySQL-tabeller og bestil efter én kolonne