Du kan bruge AddWithValue
metode som:
string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
MySqlConnection conn = new MySqlConnection(connString);
conn.Open();
MySqlCommand comm = conn.CreateCommand();
comm.CommandText = "INSERT INTO room(person,address) VALUES(@person, @address)";
comm.Parameters.AddWithValue("@person", "Myname");
comm.Parameters.AddWithValue("@address", "Myaddress");
comm.ExecuteNonQuery();
conn.Close();
ELLER
Prøv med ?
i stedet for @
, som:
string connString = ConfigurationManager.ConnectionStrings["default"].ConnectionString;
MySqlConnection conn = new MySqlConnection(connString);
conn.Open();
MySqlCommand comm = conn.CreateCommand();
comm.CommandText = "INSERT INTO room(person,address) VALUES(?person, ?address)";
comm.Parameters.Add("?person", "Myname");
comm.Parameters.Add("?address", "Myaddress");
comm.ExecuteNonQuery();
conn.Close();
Håber det hjælper...