Få placeringen af ​​xml-elementet i SQL Server 2012

Du kan bruge noget intern viden om, hvordan SQL Server implementerer XML-shredding og bruge row_number() sådan her.

declare @XML xml = 
'<Rows>
   <Row>Coating</Row>
   <Row>Drying</Row>
   <Row>Waxing</Row>
</Rows>'

select T.X.value('text()[1]', 'nvarchar(100)') as RowLabel,
       row_number() over(order by T.X) as RowNumber
from @XML.nodes('/Rows/Row') as T(X)

Ref:Unikt identifikation af XML-noder med DENSE_RANK

Eller du kan "spille det sikkert" og bruge en taltabel.

select T.X.value('text()[1]', 'nvarchar(100)') as RowLabel,
       N.Number as RowNumber
from Numbers as N
  cross apply @XML.nodes('/Rows/Row[sql:column("N.Number")]') as T(X)
where N.Number between 1 and @XML.value('count(/Rows/Row)', 'int')