SQL Server 2005 - Row_Number()

ORDER BY i ROW_NUMBER klausulen garanterer ikke rækkefølgen af ​​resultatsættet.

ROW_NUMBER bruger normalt sortering i forespørgselsplanen, hvilket resulterer i, at værdierne kommer ud forsorteret.

Dette er en bivirkning og bør ikke stoles på.

DISTINCT bruger Hash Match (Aggregate) hvilket bryder sorteringen.

Tilføj ORDER BY klausul til slutningen af ​​forespørgslen:

SELECT  DISTINCT (ID), State_Id, Name_Of_Trip, Date_Of_Travel, Creation_Date, Locking_Id, Applicant_Name, Reference_Number, State_Name
FROM    (
        SELECT  app.ID, app.State_Id, app.Name_Of_Trip, app.Date_Of_Travel,
                app.Creation_Date, app.Locking_Id, app.Applicant_Name, app.Reference_Number, 
                State.Name AS State_Name, ROW_NUMBER() OVER(ORDER BY Reference_Number DESC) as rowNum  
        FROM    Application_Leg AS app 
        INNER JOIN
                State AS state 
        ON      app.State_Id = state.ID
        WHERE   app.State_Id IN (5, 6, 8)
                AND app.Organisation_Id = 12 
                AND Leg_Number IN
                (
                SELECT  Leg_Number 
                FROM    Application_Leg as al
                INNER JOIN
                        Organisation as org
                ON      al.Organisation_Id = org.ID
                WHERE   al.ID = app.ID
                        AND org.Approval_Required = 1
                        AND Mode_Of_Transport = 1
                )
        ) AS pagedApplications
WHERE   rowNum BETWEEN 0 AND (0 + 10)
ORDER BY
        ReferenceNumber DESC

Bemærk også, at den ikke returnerer 10 forskellige resultater, vil det returnere DISTINCT af de første 10 resultater.

Hvis du vil have førstnævnte, så brug denne:

SELECT  DISTINCT TOP 10 ID, State_Id, Name_Of_Trip, Date_Of_Travel, Creation_Date, Locking_Id, Applicant_Name, Reference_Number, State_Name
FROM    (
        SELECT  app.ID, app.State_Id, app.Name_Of_Trip, app.Date_Of_Travel,
                app.Creation_Date, app.Locking_Id, app.Applicant_Name, app.Reference_Number, 
                State.Name AS State_Name
        FROM    Application_Leg AS app 
        INNER JOIN
                State AS state 
        ON      app.State_Id = state.ID
        WHERE   app.State_Id IN (5, 6, 8)
                AND app.Organisation_Id = 12 
                AND EXISTS
                (
                SELECT  Leg_Number 
                FROM    Application_Leg AS al
                INNER JOIN
                        Organisation as org
                ON      al.Organisation_Id = org.ID
                WHERE   al.ID = app.ID
                        AND al.LegNumber = app.LegNumber
                        AND org.Approval_Required = 1
                        AND Mode_Of_Transport = 1
                )
        ) AS pagedApplications
ORDER BY
        ReferenceNumber DESC