Postgres for at hente listen med kommaseparerede værdier

Aggreger efter medarbejder og brug string_agg :

select
    c.employee_id,         -- or just c.* assuming employee_id is a PK
    string_agg(ce.email, ',') as emails
from root.employee c
full outer join root.employee_email ce
    on c.employee_id = ce.employee_id
group by
    c.employee_id
order by
    c.employee_id
limit 1000
offset 0;