jeg er stadig ikke sikker på, hvad du vil.
sådan noget?
WITH group2 AS (
SELECT r.Restaurant_ID, r.Name, f.Feature
FROM Restaurants r
INNER JOIN Bridge1_Restaurant_Features b ON b.Restaurant_ID = r.Restaurant_ID
INNER JOIN Features f ON b.Feature_ID = f.Feature_ID
INNER JOIN
(
SELECT Restaurant_ID, COUNT(Feature_ID) AS FeatureCount
FROM Bridge1_Restaurant_Features
<!--- find matching features --->
WHERE Feature_ID IN ( <cfqueryparam value="#ARGUMENTS.Feature_ID#" cfsqltype="cf_sql_integer" list="true"> )
GROUP BY Restaurant_ID
<!--- having ALL of the requested features --->
HAVING COUNT(Feature_ID) = <cfqueryparam value="#listLen(ARGUMENTS.Feature_ID)#" cfsqltype="cf_sql_integer">
) ck ON ck.Restaurant_ID = r.Restaurant_Id
)
SELECT r.Name , r.Restaurant_ID, f.feature, r.Price_Range, r.Cuisine_ID, c.Cuisine,
s.State_ID, s.State, l.Location_ID, l.Area, l.State_ID, r.Name, r.Location_ID
FROM Restaurants r, Bridge1_Restaurant_Features b, Features f, Cuisine c, State s, Location l
where 0=0
AND b.Feature_ID = f.Feature_ID
AND b.Restaurant_ID = r.Restaurant_ID
AND r.Cuisine_ID = c.Cuisine_ID
AND r.Location_ID = l.Location_ID
AND l.State_ID = s.State_ID
<cfif ARGUMENTS.Feature_ID IS NOT "">
AND f.Feature_ID IN (group2.Restaurant_ID)
</cfif>
<cfif ARGUMENTS.Price_Range IS NOT "">
AND r.Price_Range IN (#ARGUMENTS.Price_Range#)
</cfif>
<cfif ARGUMENTS.Cuisine IS NOT "">
AND r.Cuisine_ID = (#ARGUMENTS.Cuisine#)
</cfif>
<cfif val(ARGUMENTS.LocationID2) IS #val(ARGUMENTS.StateID)#>
AND l.State_ID = #val(ARGUMENTS.LocationID2)#
<cfelse>
AND l.Location_ID = #val(ARGUMENTS.LocationID2)#
</cfif>