MySQL åbningstider

Hvis du ikke kan ændre tabellen, kan du bruge denne forespørgsel:

SELECT COUNT(*) 
FROM opening_hrs
WHERE (((100*HOUR(NOW())+MINUTE(NOW()) >= openTime) 
        AND (100*HOUR(NOW())+MINUTE(NOW()) <= closeTime + 2400*(closeDay-openDay)))
       OR 
       ((100*HOUR(NOW())+MINUTE(NOW()) >= openTime - 2400*(closeDay-openDay)) 
        AND (100*HOUR(NOW())+MINUTE(NOW()) <= closeTime )))
AND openDay = 1

Hvis du kan ændre tabellen til at se sådan ud:

+---------+----------+-----------+
|     day | openTime | closeTime |
+---------+----------+-----------+
|       0 | 1800     |  2400     |
|       1 | 1800     |  2400     |
|       2 | 1800     |  2400     |
|       3 | 1800     |  2400     |
|       4 | 1800     |  2400     |
|       5 | 1800     |  2400     |
|       6 | 1800     |  2400     |
|       0 |    0     |   400     |
|       1 |    0     |   400     |
|       2 |    0     |   400     |
|       3 |    0     |   400     |
|       4 |    0     |   400     |
|       5 |    0     |   400     |
|       6 |    0     |   400     |
+---------+----------+-----------+

så kan du udføre forespørgslen sådan her:

SELECT COUNT(*) 
FROM opening_hrs
WHERE (100*HOUR(NOW())+MINUTE(NOW()) >= openTime) 
AND (100*HOUR(NOW())+MINUTE(NOW()) <= closeTime)
AND day = 1

Bemærk, at der ikke er mere openDay og closeDay; bare en day kolonne. Bemærk også, at openTime er altid mindre end closeTime , så ulighederne i forespørgslen kan fungere.