Prøv:
SELECT p.id as pack_id,
XMLELEMENT(name taskgroup,
XMLATTRIBUTES(tg.id as id),
XMLAGG(XMLELEMENT(name task,
XMLATTRIBUTES(t.id as id)) as xml_task_group
FROM packages p
JOIN package_taskgroup pt ON p.id = pt.package_id
JOIN taskgroups tg on pt.taskgroup_id = tg.id
JOIN taskgroup_task tt on tg.id = tt.taskgroup_id
JOIN tasks t on tt.task_id = t.id
WHERE p.id = somePackageId
GROUP BY p.id, tg.id
Dette vil give dig alle opgavegrupperne for p.id
du har angivet.
Så:
SELECT XMLELEMENT(name package,
XMLATTRIBUTES(pack_id as id),
XMLAGG(xml_task_group))
FROM (previous SELECT here)
Dette vil give dig den struktur, du har angivet.
Detaljer:XMLAGG , XML-funktioner
Tilsluttet udvalg vil se sådan ud:
SELECT XMLELEMENT(name package,
XMLATTRIBUTES(pack_id as id),
XMLAGG(xml_task_group))
FROM (SELECT p.id as pack_id,
XMLELEMENT(name taskgroup,
XMLATTRIBUTES(tg.id as id),
XMLAGG(XMLELEMENT(name task,
XMLATTRIBUTES(t.id as id)
))) as xml_task_group
FROM packages p
JOIN package_taskgroup pt ON p.id = pt.package_id
JOIN taskgroups tg on pt.taskgroup_id = tg.id
JOIN taskgroup_task tt on tg.id = tt.taskgroup_id
JOIN tasks t on tt.task_id = t.id
WHERE p.id = somePackageId
GROUP BY p.id, tg.id) t
GROUP BY pack_id
Jeg kopierede simpelthen det første valg til FROM
andet afsnit.