Du mangler kunde-id-kolonnen i kontotabellen. Jeg har tilføjet nogle flere rækker med data for at oprette testcasen til dit krav.
drop table acct;
drop table branch;
drop table customer;
create table branch(bid number primary key, addr_street varchar2(100), addr_city varchar2(100), addr_p varchar2(20));
insert into branch values(901,'Nicholson Street','Edinburgh','EH11 5AB');
insert into branch values(906,'East End Garden','Glasgow','G181QP');
insert into branch values(912,'Fredrick Street','London','LA112AS');
insert into branch values(918,'Zink Terrace','Edinburgh','EH149UU');
commit;
select * from branch;
Output:
BID ADDR_STREET ADDR_CITY ADDR_P
901 Nicholson Street Edinburgh EH11 5AB
906 East End Garden Glasgow G181QP
912 Fredrick Street London LA112AS
918 Zink Terrace Edinburgh EH149UU
create table customer(custid number primary key, caddr_street varchar2(100), caddr_city varchar2(100),
caddr_p varchar2(10), fname varchar2(100), lname varchar2(100));
insert into customer values(1002,'Adam Street','Edinburgh','EH112LQ','Jack','Smith');
insert into customer values(1003,'Adam Street','Edinburgh','EH112LQ','Anna','Smith');
insert into customer values(1004,'New Tweed','Edinburgh','EH1158L','Liam','Bain');
insert into customer values(1005,'Dundas Street','Edinburgh','EH119MN','Usman','Afaque');
insert into customer values(1006,'St Andres Square','Edinburgh','EH12LNM','Claire','Mackintosh');
commit;
select * from customer;
Output:
CUSTID CADDR_STREET CADDR_CITY CADDR_P FNAME LNAME
1002 Adam Street Edinburgh EH112LQ Jack Smith
1003 Adam Street Edinburgh EH112LQ Anna Smith
1004 New Tweed Edinburgh EH1158L Liam Bain
1005 Dundas Street Edinburgh EH119MN Usman Afaque
1006 St Andres Square Edinburgh EH12LNM Claire Mackintosh
create table acct(accnum number primary key, acctype varchar2(20), balance number, bid number
constraint acct_fk1 references branch(bid),
inrate number, LIMITOFFREEOD number, OPENDATE date, custid number
constraint acct_fk2 references customer(custid));
insert into acct values(1001,'current',820.5,901,0.005,800,to_date('01-MAY-11','dd-mon-yy'),1002);
insert into acct values(1010,'saving',2155,906,0.02,0,to_date('08-MAR-10','dd-mon-yy'),1002);
insert into acct values(1002,'current',2600,912,0.005,1000,to_date('10-APR-13','dd-mon-yy'),1006);
insert into acct values(1011,'saving',4140,918,0.02,0,to_date('24-OCT-13','dd-mon-yy'),1004);
insert into acct values(1012,'saving',4155,906,0.02,0,to_date('08-MAR-10','dd-mon-yy'),1004);
insert into acct values(1013,'current',2600,918,0.005,1000,to_date('10-APR-13','dd-mon-yy'),1004);
commit;
select * from acct;
Output:
ACCNUM ACCTYPE BALANCE BID INRATE LIMITOFFREEOD OPENDATE CUSTID
1001 current 820.5 901 .005 800 01-MAY-11 1002
1010 saving 2155 906 .02 0 08-MAR-10 1002
1002 current 2600 912 .005 1000 10-APR-13 1006
1011 saving 4140 918 .02 0 24-OCT-13 1004
1012 saving 4155 906 .02 0 08-MAR-10 1004
1013 current 2600 918 .005 1000 10-APR-13 1004
select y.fname, y.lname, y.balance, y.bid,ac.accnum,ac.acctype,ac.LIMITOFFREEOD
from (select *
from (select b.bid, c.custid, a.accnum,a.balance,
row_number() over(partition by b.bid order by a.balance desc) rn,
c.fname, c.lname
from acct a
inner join
branch b
on a.bid = b.bid
inner join
customer c
on a.custid = c.custid
where a.acctype = 'saving') x
where x.rn = 1) y
left join
acct ac
on y.custid = ac.custid
and y.bid = ac.bid
and ac.acctype = 'current';
Output:
FNAME LNAME BALANCE BID ACCNUM ACCTYPE LIMITOFFREEOD
Liam Bain 4140 918 1013 current 1000
Liam Bain 4155 906 NULL NULL NULL