sql >> Database teknologi >  >> RDS >> Oracle

en sql-forespørgsel til at sammenligne resultaterne af følgende forespørgsler

Der er mange ting usagt. Jeg håber, du får klarere krav i dit daglige arbejde...Her er i hvert fald en simulering af din situation. Det er baseret på den antagelse, at dagene med data (én om ugen) er de samme i 2007 som i 2008:

SQL> create table lnd_wkly_plan_rx_summary (pd_end_dt,nrx_cnt)
  2  as
  3  select date '2008-09-07', 100000 from dual union all
  4  select date '2008-09-07', 536619.92 from dual union all
  5  select date '2008-09-14', 698082.03 from dual union all
  6  select date '2008-09-21', 403604.59 from dual union all
  7  select date '2008-09-21', 200000 from dual union all
  8  select date '2008-09-21', 100000 from dual union all
  9  select date '2008-09-28', 702457.36 from dual union all
 10  select date '2007-09-07', 400000 from dual union all
 11  select date '2007-09-14', 450000 from dual union all
 12  select date '2007-09-21', 500000 from dual union all
 13  select date '2007-09-28', 550000 from dual union all
 14  select date '2007-09-28', 100000 from dual
 15  /

Tabel is aangemaakt.

Og dine oprindelige forespørgsler, lidt ændret.

SQL> SELECT pd_end_dt
  2       , SUM(nrx_cnt) Total_Count
  3    FROM lnd_wkly_plan_rx_summary
  4   WHERE pd_end_dt >= date '2008-09-01'
  5     AND pd_end_dt <  date '2008-09-30'
  6   GROUP BY pd_end_dt
  7  /

PD_END_DT           TOTAL_COUNT
------------------- -----------
07-09-2008 00:00:00   636619,92
14-09-2008 00:00:00   698082,03
21-09-2008 00:00:00   703604,59
28-09-2008 00:00:00   702457,36

4 rijen zijn geselecteerd.

SQL> SELECT pd_end_dt
  2       , SUM(nrx_cnt) Total_Count
  3    FROM lnd_wkly_plan_rx_summary
  4   WHERE pd_end_dt >= date '2007-09-01'
  5     AND pd_end_dt <  date '2007-09-30'
  6   GROUP BY pd_end_dt
  7  /

PD_END_DT           TOTAL_COUNT
------------------- -----------
07-09-2007 00:00:00      400000
14-09-2007 00:00:00      450000
21-09-2007 00:00:00      500000
28-09-2007 00:00:00      650000

4 rijen zijn geselecteerd.

Og forespørgslen, som du kan sammenligne data fra 2007 og 2008 med:

SQL> select to_char(pd_end_dt,'dd-mm') day_and_month
  2       , sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) sum2007
  3       , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) sum2008
  4       , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end)
  5         - sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) difference
  6       , (  sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end)
  7          - sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end)
  8         ) / sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) * 100 percentage_difference
  9    from lnd_wkly_plan_rx_summary
 10   where (  (   pd_end_dt >= date '2007-09-01'
 11            and pd_end_dt <  date '2007-09-30'
 12            )
 13         or (   pd_end_dt >= date '2008-09-07'
 14            and pd_end_dt <  date '2008-09-30'
 15            )
 16         )
 17   group by to_char(pd_end_dt,'dd-mm')
 18  /

DAY_A    SUM2007    SUM2008 DIFFERENCE PERCENTAGE_DIFFERENCE
----- ---------- ---------- ---------- ---------------------
07-09     400000  636619,92  236619,92            37,1681615
14-09     450000  698082,03  248082,03            35,5376617
21-09     500000  703604,59  203604,59            28,9373595
28-09     650000  702457,36   52457,36            7,46769313

4 rijen zijn geselecteerd.

Selvom det er ret ordrigt, synes jeg, det taler for sig selv. Du kan godt lide følgende omskrivning, da den ikke gentager de samlede funktioner så meget som i forespørgslen ovenfor:

SQL> select day_and_month
  2       , sum2007
  3       , sum2008
  4       , sum2008-sum2007 difference
  5       , 100*(sum2008-sum2007)/sum2008 percentage_difference
  6    from ( select to_char(pd_end_dt,'dd-mm') day_and_month
  7                , sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) sum2007
  8                , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) sum2008
  9             from lnd_wkly_plan_rx_summary
 10            where (   pd_end_dt >= date '2007-09-01'
 11                  and pd_end_dt <  date '2007-09-30'
 12                  )
 13               or (   pd_end_dt >= date '2008-09-07'
 14                  and pd_end_dt <  date '2008-09-30'
 15                  )
 16            group by to_char(pd_end_dt,'dd-mm')
 17         )
 18  /

DAY_A    SUM2007    SUM2008 DIFFERENCE PERCENTAGE_DIFFERENCE
----- ---------- ---------- ---------- ---------------------
07-09     400000  636619,92  236619,92            37,1681615
14-09     450000  698082,03  248082,03            35,5376617
21-09     500000  703604,59  203604,59            28,9373595
28-09     650000  702457,36   52457,36            7,46769313

4 rijen zijn geselecteerd.

Håber dette hjælper.

Med venlig hilsen Rob.



  1. SQL Fuzzy Matching

  2. Java MySQL-integration med ArrayLists

  3. Få ID'et for en ny post indsat i en database fra den returnerede Uri

  4. Brug af rekursiv CTE med Ecto